HİDROJEN ATOMU KOMPLE DALGA FONK.;n=3
10/8/2006
(10) n = 3 ~ l = 2 ~ m = 2
Ψ322 (r,θ,φ) = R32 (r) Y2² (θ,φ)
Y2² (θ,φ) = [15/32π]¹/² (sin²θ) exp(2iφ)
Ψ322 =(2/27)[3/16π]¹/² (z/3a)³/² (zr/a)² (sin²θ) exp[-(zr/3a)+2iφ]
(11) n = 3 ~ l = 1 ~ m = -1
-1
Ψ31-1 (r,θ,φ) = R31 (r) Y1 (θ,φ)
R31(r) = (4/9)(2)¹/² (z/3a)³/²(zr/a) (1 -[zr/6a]) exp(-zr/3a)
-1
Y1 (θ,φ) = [3/8π]¹/² (sinθ) exp(-iφ)
Ψ31-1 = (4/9)[3/4π]¹/² (z/3a)³/²(zr/a)(sinθ) (1 -[zr/6a]) exp(-(zr/3a)-iφ)
(12) n = 3 ~ l = 1 ~ m = 0
Ψ310 (r,θ,φ) = R31 (r) Y1º (θ,φ)
Y1º (θ,φ) = [3/4π]¹/² (cosθ)
Ψ310 = (4/9)[3/2π]¹/² (z/3a)³/²(zr/a)(cosθ)(1 -[zr/6a]) exp(-zr/3a)
(13) n = 3 ~ l = 1 ~ m = 1
Ψ311 (r,θ,φ) = R31 (r) Y1¹ (θ,φ)
Y1¹ (θ,φ) = - [3/8π]¹/² (sinθ) exp(iφ)
Ψ311 =-(4/9)[3/4π]¹/²(z/3a)³/²(zr/a)(sinθ)(1 -[zr/6a]) exp(-(zr/3a)+iφ)
(14) n = 3 ~ l = 0 ~ m = 0
Ψ300 (r,θ,φ) = R30 (r) Y0º (θ,φ)
R30(r) = 2 (z/3a)³/² [1- (2zr/3a)+(2z²r²/27a²)] exp (-zr/3a)
Y0º (θ,φ) = [1/4π]¹/²
Ψ300 = 2 [1/4π]¹/²(z/3a)³/² [1- (2zr/3a)+(2z²r²/27a²)] exp (-zr/3a)
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